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1303134357243 = 3434378119081
BaseRepresentation
bin10010111101101000110…
…111000100011011111011
311121120121200012022001110
4102331220313010123323
5132322304343412433
62434352431451403
7163101612163215
oct22755067043373
94546550168043
101303134357243
11462724410184
12190681086b63
1395b675917b4
14471019675b5
1523d6e1a8963
hex12f68dc46fb

1303134357243 has 4 divisors (see below), whose sum is σ = 1737512476328. Its totient is φ = 868756238160.

The previous prime is 1303134357233. The next prime is 1303134357253. The reversal of 1303134357243 is 3427534313031.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1303134357233) and next prime (1303134357253).

It is not a de Polignac number, because 1303134357243 - 28 = 1303134356987 is a prime.

It is a super-2 number, since 2×13031343572432 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1303134357233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 217189059538 + ... + 217189059543.

It is an arithmetic number, because the mean of its divisors is an integer number (434378119082).

Almost surely, 21303134357243 is an apocalyptic number.

1303134357243 is a deficient number, since it is larger than the sum of its proper divisors (434378119085).

1303134357243 is an equidigital number, since it uses as much as digits as its factorization.

1303134357243 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 434378119084.

The product of its (nonzero) digits is 272160, while the sum is 39.

The spelling of 1303134357243 in words is "one trillion, three hundred three billion, one hundred thirty-four million, three hundred fifty-seven thousand, two hundred forty-three".

Divisors: 1 3 434378119081 1303134357243