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13032000113001 = 38252835263649
BaseRepresentation
bin1011110110100011111110…
…1111001100100101101001
31201010211212111100200212220
42331220333233030211221
53202004014012104001
643414452422024253
72513350053152442
oct275507757144551
951124774320786
1013032000113001
114174927358281
121565832578089
13736bb253711c
14330a75d582c9
15178ed3b96c36
hexbda3fbcc969

13032000113001 has 8 divisors (see below), whose sum is σ = 17376024506400. Its totient is φ = 8687987897472.

The previous prime is 13032000112979. The next prime is 13032000113071. The reversal of 13032000113001 is 10031100023031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13032000113001 - 223 = 13031991724393 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13032000113071) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 155976 + ... + 5107673.

It is an arithmetic number, because the mean of its divisors is an integer number (2172003063300).

Almost surely, 213032000113001 is an apocalyptic number.

It is an amenable number.

13032000113001 is a deficient number, since it is larger than the sum of its proper divisors (4344024393399).

13032000113001 is an equidigital number, since it uses as much as digits as its factorization.

13032000113001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6088935.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 13032000113001 its reverse (10031100023031), we get a palindrome (23063100136032).

The spelling of 13032000113001 in words is "thirteen trillion, thirty-two billion, one hundred thirteen thousand, one".

Divisors: 1 3 825283 2475849 5263649 15790947 4344000037667 13032000113001