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13032002113 = 132843352607
BaseRepresentation
bin11000010001100010…
…01001001001000001
31020122020000022002221
430020301021021001
5203142143031423
65553053011041
7640642122154
oct141061111101
936566008087
1013032002113
115588253089
122638483a81
1312c8bc8070
148b8ad9c9b
15514173e5d
hex308c49241

13032002113 has 8 divisors (see below), whose sum is σ = 14039440128. Its totient is φ = 12025275024.

The previous prime is 13032002083. The next prime is 13032002117. The reversal of 13032002113 is 31120023031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13032002113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13032002117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 139345 + ... + 213262.

It is an arithmetic number, because the mean of its divisors is an integer number (1754930016).

Almost surely, 213032002113 is an apocalyptic number.

13032002113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

13032002113 is a deficient number, since it is larger than the sum of its proper divisors (1007438015).

13032002113 is a wasteful number, since it uses less digits than its factorization.

13032002113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 355463.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 13032002113 its reverse (31120023031), we get a palindrome (44152025144).

The spelling of 13032002113 in words is "thirteen billion, thirty-two million, two thousand, one hundred thirteen".

Divisors: 1 13 2843 36959 352607 4583891 1002461701 13032002113