13032011133121 has 4 divisors (see below), whose sum is σ = 13032762231744. Its totient is φ = 13031260034500.

The previous prime is 13032011133061. The next prime is 13032011133137. The reversal of 13032011133121 is 12133111023031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13032011133121 - 2¹⁹ = 13032010608833 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13032011133092 and 13032011133101.

It is not an unprimeable number, because it can be changed into a prime (13032011133191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 375523285 + ... + 375557986.

It is an arithmetic number, because the mean of its divisors is an integer number (3258190557936).

Almost surely, 2^{13032011133121} is an apocalyptic number.

It is an amenable number.

13032011133121 is a deficient number, since it is larger than the sum of its proper divisors (751098623).

13032011133121 is an equidigital number, since it uses as much as digits as its factorization.

13032011133121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 751098622.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 13032011133121 its reverse (12133111023031), we get a palindrome (25165122156152).

The spelling of 13032011133121 in words is "thirteen trillion, thirty-two billion, eleven million, one hundred thirty-three thousand, one hundred twenty-one".