Base | Representation |
---|---|
bin | 1011110110100100000011… |
… | …1011000110100001011011 |
3 | 1201010211220212210121221111 |
4 | 2331221000323012201123 |
5 | 3202004034110323344 |
6 | 43414454412321151 |
7 | 2513350414245415 |
oct | 275510073064133 |
9 | 51124825717844 |
10 | 13032020011099 |
11 | 4174937608a91 |
12 | 15658391731b7 |
13 | 736bb66b304b |
14 | 330a788579b5 |
15 | 178ed57c7834 |
hex | bda40ec685b |
13032020011099 has 4 divisors (see below), whose sum is σ = 13119483232800. Its totient is φ = 12944556789400.
The previous prime is 13032020011069. The next prime is 13032020011139. The reversal of 13032020011099 is 99011002023031.
13032020011099 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13032020011099 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13032020011099.
It is not an unprimeable number, because it can be changed into a prime (13032020011069) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43731610627 + ... + 43731610924.
It is an arithmetic number, because the mean of its divisors is an integer number (3279870808200).
Almost surely, 213032020011099 is an apocalyptic number.
13032020011099 is a deficient number, since it is larger than the sum of its proper divisors (87463221701).
13032020011099 is an equidigital number, since it uses as much as digits as its factorization.
13032020011099 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 87463221700.
The product of its (nonzero) digits is 2916, while the sum is 31.
The spelling of 13032020011099 in words is "thirteen trillion, thirty-two billion, twenty million, eleven thousand, ninety-nine".
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