Base | Representation |
---|---|
bin | 111100101011110110… |
… | …0010001000101101011 |
3 | 110110101020112011200201 |
4 | 1321113230101011223 |
5 | 4113343440203003 |
6 | 135511315013031 |
7 | 12262312525411 |
oct | 1712754210553 |
9 | 413336464621 |
10 | 130320241003 |
11 | 502a5418a17 |
12 | 2130bb9a177 |
13 | c39b33b654 |
14 | 6443c2b2b1 |
15 | 35cb01eb1d |
hex | 1e57b1116b |
130320241003 has 4 divisors (see below), whose sum is σ = 131119751848. Its totient is φ = 129520730160.
The previous prime is 130320240979. The next prime is 130320241021. The reversal of 130320241003 is 300142023031.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 300142023031 = 13337 ⋅22504463.
It is a cyclic number.
It is not a de Polignac number, because 130320241003 - 213 = 130320232811 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130320211003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 399755178 + ... + 399755503.
It is an arithmetic number, because the mean of its divisors is an integer number (32779937962).
Almost surely, 2130320241003 is an apocalyptic number.
130320241003 is a deficient number, since it is larger than the sum of its proper divisors (799510845).
130320241003 is an equidigital number, since it uses as much as digits as its factorization.
130320241003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 799510844.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 130320241003 its reverse (300142023031), we get a palindrome (430462264034).
The spelling of 130320241003 in words is "one hundred thirty billion, three hundred twenty million, two hundred forty-one thousand, three".
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