13032255433 has 4 divisors (see below), whose sum is σ = 13044179908. Its totient is φ = 13020330960.

The previous prime is 13032255427. The next prime is 13032255473. The reversal of 13032255433 is 33455223031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10807057849 + 2225197584 = 103957^2 + 47172^2 .

It is a cyclic number.

It is not a de Polignac number, because 13032255433 - 2²⁹ = 12495384521 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13032255395 and 13032255404.

It is not an unprimeable number, because it can be changed into a prime (13032255473) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5960598 + ... + 5962783.

It is an arithmetic number, because the mean of its divisors is an integer number (3261044977).

Almost surely, 2^13032255433 is an apocalyptic number.

It is an amenable number.

13032255433 is a deficient number, since it is larger than the sum of its proper divisors (11924475).

13032255433 is a wasteful number, since it uses less digits than its factorization.

13032255433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11924474.

The product of its (nonzero) digits is 32400, while the sum is 31.

Adding to 13032255433 its reverse (33455223031), we get a palindrome (46487478464).

The spelling of 13032255433 in words is "thirteen billion, thirty-two million, two hundred fifty-five thousand, four hundred thirty-three".