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130330003010001 = 343443334336667
BaseRepresentation
bin11101101000100011010001…
…100010000111000111010001
3122002110102111222220010211120
4131220203101202013013101
5114040311321232310001
61141104435443432453
736311013654050364
oct3550432142070721
9562412458803746
10130330003010001
113858870a003a63
121274a9b2385729
1357950b3290c42
142428011cd00db
1510102b0c78236
hex7688d18871d1

130330003010001 has 4 divisors (see below), whose sum is σ = 173773337346672. Its totient is φ = 86886668673332.

The previous prime is 130330003009939. The next prime is 130330003010029. The reversal of 130330003010001 is 100010300033031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130330003010001 - 26 = 130330003009937 is a prime.

It is not an unprimeable number, because it can be changed into a prime (130330003010101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21721667168331 + ... + 21721667168336.

It is an arithmetic number, because the mean of its divisors is an integer number (43443334336668).

Almost surely, 2130330003010001 is an apocalyptic number.

It is an amenable number.

130330003010001 is a deficient number, since it is larger than the sum of its proper divisors (43443334336671).

130330003010001 is an equidigital number, since it uses as much as digits as its factorization.

130330003010001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43443334336670.

The product of its (nonzero) digits is 81, while the sum is 15.

Adding to 130330003010001 its reverse (100010300033031), we get a palindrome (230340303043032).

The spelling of 130330003010001 in words is "one hundred thirty trillion, three hundred thirty billion, three million, ten thousand, one".

Divisors: 1 3 43443334336667 130330003010001