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13033001021113 = 171399547996511
BaseRepresentation
bin1011110110100111101101…
…1001010110111010111001
31201010221110020202002200201
42331221323121112322321
53202013041230133423
643415140015002201
72513413625555053
oct275517331267271
951127406662621
1013033001021113
1141752a0341367
121565a71809361
13737011a01748
14330b2cc608d3
151790419a72ad
hexbda7b656eb9

13033001021113 has 8 divisors (see below), whose sum is σ = 13809512102400. Its totient is φ = 12257585935680.

The previous prime is 13033001021081. The next prime is 13033001021119. The reversal of 13033001021113 is 31112010033031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13033001021113 - 25 = 13033001021081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13033001021119) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 273974473 + ... + 274022038.

It is an arithmetic number, because the mean of its divisors is an integer number (1726189012800).

Almost surely, 213033001021113 is an apocalyptic number.

It is an amenable number.

13033001021113 is a deficient number, since it is larger than the sum of its proper divisors (776511081287).

13033001021113 is a wasteful number, since it uses less digits than its factorization.

13033001021113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 547997927.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 13033001021113 its reverse (31112010033031), we get a palindrome (44145011054144).

The spelling of 13033001021113 in words is "thirteen trillion, thirty-three billion, one million, twenty-one thousand, one hundred thirteen".

Divisors: 1 17 1399 23783 547996511 9315940687 766647118889 13033001021113