Base | Representation |
---|---|
bin | 1011110110101000110100… |
… | …1111000011101111100011 |
3 | 1201010222020002220121020202 |
4 | 2331222031033003233203 |
5 | 3202014144334423021 |
6 | 43415225425455415 |
7 | 2513424221516261 |
oct | 275521517035743 |
9 | 51128202817222 |
10 | 13033300311011 |
11 | 4175434280292 |
12 | 1565b35aa156b |
13 | 73705ba11266 |
14 | 330b5a8cb431 |
15 | 17905cdc5a0b |
hex | bda8d3c3be3 |
13033300311011 has 4 divisors (see below), whose sum is σ = 13033307551992. Its totient is φ = 13033293070032.
The previous prime is 13033300311007. The next prime is 13033300311029. The reversal of 13033300311011 is 11011300333031.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 13033300311011 - 22 = 13033300311007 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13033300310011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1400420 + ... + 5294126.
It is an arithmetic number, because the mean of its divisors is an integer number (3258326887998).
Almost surely, 213033300311011 is an apocalyptic number.
13033300311011 is a deficient number, since it is larger than the sum of its proper divisors (7240981).
13033300311011 is an equidigital number, since it uses as much as digits as its factorization.
13033300311011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7240980.
The product of its (nonzero) digits is 243, while the sum is 20.
Adding to 13033300311011 its reverse (11011300333031), we get a palindrome (24044600644042).
The spelling of 13033300311011 in words is "thirteen trillion, thirty-three billion, three hundred million, three hundred eleven thousand, eleven".
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