Base | Representation |
---|---|
bin | 1011110110101000111001… |
… | …1011010011111001010001 |
3 | 1201010222021111112011010212 |
4 | 2331222032123103321101 |
5 | 3202014214444100423 |
6 | 43415231422133505 |
7 | 2513424553441451 |
oct | 275521633237121 |
9 | 51128244464125 |
10 | 13033320300113 |
11 | 4175444593403 |
12 | 1565b40721295 |
13 | 737062bbc729 |
14 | 330b5d411d61 |
15 | 17905ea23578 |
hex | bda8e6d3e51 |
13033320300113 has 8 divisors (see below), whose sum is σ = 13101810085056. Its totient is φ = 12964973950800.
The previous prime is 13033320300103. The next prime is 13033320300163. The reversal of 13033320300113 is 31100302333031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13033320300113 - 24 = 13033320300097 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (13033320300103) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35676698 + ... + 36040163.
It is an arithmetic number, because the mean of its divisors is an integer number (1637726260632).
Almost surely, 213033320300113 is an apocalyptic number.
It is an amenable number.
13033320300113 is a deficient number, since it is larger than the sum of its proper divisors (68489784943).
13033320300113 is an equidigital number, since it uses as much as digits as its factorization.
13033320300113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 71717815.
The product of its (nonzero) digits is 1458, while the sum is 23.
Adding to 13033320300113 its reverse (31100302333031), we get a palindrome (44133622633144).
The spelling of 13033320300113 in words is "thirteen trillion, thirty-three billion, three hundred twenty million, three hundred thousand, one hundred thirteen".
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