130333435433 has 4 divisors (see below), whose sum is σ = 130334220288. Its totient is φ = 130332650580.

The previous prime is 130333435409. The next prime is 130333435459. The reversal of 130333435433 is 334534333031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 130333435433 - 2¹⁴ = 130333419049 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130333435393 and 130333435402.

It is not an unprimeable number, because it can be changed into a prime (130333435483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34541 + ... + 511722.

It is an arithmetic number, because the mean of its divisors is an integer number (32583555072).

Almost surely, 2^130333435433 is an apocalyptic number.

It is an amenable number.

130333435433 is a deficient number, since it is larger than the sum of its proper divisors (784855).

130333435433 is an equidigital number, since it uses as much as digits as its factorization.

130333435433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 784854.

The product of its (nonzero) digits is 174960, while the sum is 35.

Adding to 130333435433 its reverse (334534333031), we get a palindrome (464867768464).

The spelling of 130333435433 in words is "one hundred thirty billion, three hundred thirty-three million, four hundred thirty-five thousand, four hundred thirty-three".