Base | Representation |
---|---|
bin | 11000010001110010… |
… | …01101000000111011 |
3 | 1020122100222122121212 |
4 | 30020321031000323 |
5 | 203143213141011 |
6 | 5553210153335 |
7 | 640666102442 |
oct | 141071150073 |
9 | 36570878555 |
10 | 13034115131 |
11 | 5589466684 |
12 | 263912284b |
13 | 12c9487a7b |
14 | 8b90c9d59 |
15 | 51444008b |
hex | 308e4d03b |
13034115131 has 4 divisors (see below), whose sum is σ = 13038367992. Its totient is φ = 13029862272.
The previous prime is 13034115119. The next prime is 13034115139. The reversal of 13034115131 is 13151143031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13034115131 - 226 = 12967006267 is a prime.
It is a super-2 number, since 2×130341151312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13034115097 and 13034115106.
It is not an unprimeable number, because it can be changed into a prime (13034115139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2121830 + ... + 2127963.
It is an arithmetic number, because the mean of its divisors is an integer number (3259591998).
Almost surely, 213034115131 is an apocalyptic number.
13034115131 is a deficient number, since it is larger than the sum of its proper divisors (4252861).
13034115131 is an equidigital number, since it uses as much as digits as its factorization.
13034115131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4252860.
The product of its (nonzero) digits is 540, while the sum is 23.
Adding to 13034115131 its reverse (13151143031), we get a palindrome (26185258162).
The spelling of 13034115131 in words is "thirteen billion, thirty-four million, one hundred fifteen thousand, one hundred thirty-one".
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