Base | Representation |
---|---|
bin | 1011110110101100101000… |
… | …0110010111101001001001 |
3 | 1201011001212021100111112220 |
4 | 2331223022012113221021 |
5 | 3202023242242142101 |
6 | 43415515024124253 |
7 | 2513461431143526 |
oct | 275531206275111 |
9 | 51131767314486 |
10 | 13034321443401 |
11 | 4175908718155 |
12 | 156617ba66689 |
13 | 73719243a0cb |
14 | 330c1637a14d |
15 | 1790bc87d636 |
hex | bdaca197a49 |
13034321443401 has 8 divisors (see below), whose sum is σ = 17379146277024. Its totient is φ = 8689522119360.
The previous prime is 13034321443397. The next prime is 13034321443417. The reversal of 13034321443401 is 10434412343031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13034321443401 - 22 = 13034321443397 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13034321243401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5151495 + ... + 7253036.
It is an arithmetic number, because the mean of its divisors is an integer number (2172393284628).
Almost surely, 213034321443401 is an apocalyptic number.
It is an amenable number.
13034321443401 is a deficient number, since it is larger than the sum of its proper divisors (4344824833623).
13034321443401 is a wasteful number, since it uses less digits than its factorization.
13034321443401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12754791.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 13034321443401 its reverse (10434412343031), we get a palindrome (23468733786432).
The spelling of 13034321443401 in words is "thirteen trillion, thirty-four billion, three hundred twenty-one million, four hundred forty-three thousand, four hundred one".
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