Base | Representation |
---|---|
bin | 11101101000110101101011… |
… | …101001001001001101011001 |
3 | 122002112022112110222200221001 |
4 | 131220311223221021031121 |
5 | 114041122311203222131 |
6 | 1141121505032545001 |
7 | 36312313530160141 |
oct | 3550655351111531 |
9 | 562468473880831 |
10 | 130349768414041 |
11 | 38596032070620 |
12 | 127527a9852161 |
13 | 5796c1318a6a7 |
14 | 2428d68d89921 |
15 | 1010a6b104261 |
hex | 768d6ba49359 |
130349768414041 has 8 divisors (see below), whose sum is σ = 146042983776384. Its totient is φ = 115297092454320.
The previous prime is 130349768414029. The next prime is 130349768414141. The reversal of 130349768414041 is 140414867943031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 130349768414041 - 231 = 130347620930393 is a prime.
It is not an unprimeable number, because it can be changed into a prime (130349768414141) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 160134850225 + ... + 160134851038.
It is an arithmetic number, because the mean of its divisors is an integer number (18255372972048).
Almost surely, 2130349768414041 is an apocalyptic number.
130349768414041 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
130349768414041 is a deficient number, since it is larger than the sum of its proper divisors (15693215362343).
130349768414041 is a wasteful number, since it uses less digits than its factorization.
130349768414041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 320269701311.
The product of its (nonzero) digits is 6967296, while the sum is 55.
The spelling of 130349768414041 in words is "one hundred thirty trillion, three hundred forty-nine billion, seven hundred sixty-eight million, four hundred fourteen thousand, forty-one".
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