Base | Representation |
---|---|
bin | 111100101101001110… |
… | …1111011000001111001 |
3 | 110110111111011020110212 |
4 | 1321122131323001321 |
5 | 4113442400443111 |
6 | 135520101120505 |
7 | 12263416422626 |
oct | 1713235730171 |
9 | 413444136425 |
10 | 130366812281 |
11 | 50319737682 |
12 | 213236b9135 |
13 | c3a7b96214 |
14 | 644a0b134d |
15 | 35d016d98b |
hex | 1e5a77b079 |
130366812281 has 4 divisors (see below), whose sum is σ = 130396106064. Its totient is φ = 130337518500.
The previous prime is 130366812263. The next prime is 130366812337. The reversal of 130366812281 is 182218663031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 130366812281 - 210 = 130366811257 is a prime.
It is a super-2 number, since 2×1303668122812 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130366812481) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14640215 + ... + 14649116.
It is an arithmetic number, because the mean of its divisors is an integer number (32599026516).
Almost surely, 2130366812281 is an apocalyptic number.
It is an amenable number.
130366812281 is a deficient number, since it is larger than the sum of its proper divisors (29293783).
130366812281 is an equidigital number, since it uses as much as digits as its factorization.
130366812281 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29293782.
The product of its (nonzero) digits is 82944, while the sum is 41.
The spelling of 130366812281 in words is "one hundred thirty billion, three hundred sixty-six million, eight hundred twelve thousand, two hundred eighty-one".
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