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130384241969 = 317411306757
BaseRepresentation
bin111100101101110000…
…0011010010100110001
3110110112200221202111212
41321123200122110301
54114011331220334
6135521522445505
712264020525222
oct1713340322461
9413480852455
10130384241969
1150328561883
1221329503895
13c3ab689747
14644c52b249
1535d1962ece
hex1e5b81a531

130384241969 has 4 divisors (see below), whose sum is σ = 130795549044. Its totient is φ = 129972934896.

The previous prime is 130384241921. The next prime is 130384242029. The reversal of 130384241969 is 969142483031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6575263744 + 123808978225 = 81088^2 + 351865^2 .

It is a cyclic number.

It is not a de Polignac number, because 130384241969 - 232 = 126089274673 is a prime.

It is a super-2 number, since 2×1303842419692 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (130384240969) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 205653062 + ... + 205653695.

It is an arithmetic number, because the mean of its divisors is an integer number (32698887261).

Almost surely, 2130384241969 is an apocalyptic number.

It is an amenable number.

130384241969 is a deficient number, since it is larger than the sum of its proper divisors (411307075).

130384241969 is an equidigital number, since it uses as much as digits as its factorization.

130384241969 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 411307074.

The product of its (nonzero) digits is 1119744, while the sum is 50.

The spelling of 130384241969 in words is "one hundred thirty billion, three hundred eighty-four million, two hundred forty-one thousand, nine hundred sixty-nine".

Divisors: 1 317 411306757 130384241969