Base | Representation |
---|---|
bin | 11000010010011111… |
… | …01011000000011001 |
3 | 1020122210001220012112 |
4 | 30021033223000121 |
5 | 203201220131040 |
6 | 5553540322105 |
7 | 641100133466 |
oct | 141117530031 |
9 | 36583056175 |
10 | 13040005145 |
11 | 5591819962 |
12 | 263b0a3335 |
13 | 12ca76a99b |
14 | 8b9bc066d |
15 | 514c05365 |
hex | 3093eb019 |
13040005145 has 4 divisors (see below), whose sum is σ = 15648006180. Its totient is φ = 10432004112.
The previous prime is 13040005123. The next prime is 13040005163. The reversal of 13040005145 is 54150004031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 9264640009 + 3775365136 = 96253^2 + 61444^2 .
It is a cyclic number.
It is not a de Polignac number, because 13040005145 - 222 = 13035810841 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13040005145.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1304000510 + ... + 1304000519.
It is an arithmetic number, because the mean of its divisors is an integer number (3912001545).
Almost surely, 213040005145 is an apocalyptic number.
It is an amenable number.
13040005145 is a deficient number, since it is larger than the sum of its proper divisors (2608001035).
13040005145 is an equidigital number, since it uses as much as digits as its factorization.
13040005145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2608001034.
The product of its (nonzero) digits is 1200, while the sum is 23.
Adding to 13040005145 its reverse (54150004031), we get a palindrome (67190009176).
The spelling of 13040005145 in words is "thirteen billion, forty million, five thousand, one hundred forty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •