Base | Representation |
---|---|
bin | 11000010010011111… |
… | …01011000001110011 |
3 | 1020122210001220022212 |
4 | 30021033223001303 |
5 | 203201220131420 |
6 | 5553540322335 |
7 | 641100133655 |
oct | 141117530163 |
9 | 36583056285 |
10 | 13040005235 |
11 | 5591819a34 |
12 | 263b0a33ab |
13 | 12ca76aa3a |
14 | 8b9bc06d5 |
15 | 514c053c5 |
hex | 3093eb073 |
13040005235 has 16 divisors (see below), whose sum is σ = 16476096000. Its totient is φ = 9880245216.
The previous prime is 13040005229. The next prime is 13040005249. The reversal of 13040005235 is 53250004031.
13040005235 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 13040005235 - 24 = 13040005219 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13040005235.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 372662 + ... + 406148.
It is an arithmetic number, because the mean of its divisors is an integer number (1029756000).
Almost surely, 213040005235 is an apocalyptic number.
13040005235 is a deficient number, since it is larger than the sum of its proper divisors (3436090765).
13040005235 is a wasteful number, since it uses less digits than its factorization.
13040005235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 37610.
The product of its (nonzero) digits is 1800, while the sum is 23.
Adding to 13040005235 its reverse (53250004031), we get a palindrome (66290009266).
The spelling of 13040005235 in words is "thirteen billion, forty million, five thousand, two hundred thirty-five".
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