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130402311033 = 343467437011
BaseRepresentation
bin111100101110010010…
…1010101101101111001
3110110120221221202121110
41321130211111231321
54114030442423113
6135523410030533
712264330232551
oct1713445255571
9413527852543
10130402311033
1150337783395
1221333578449
13c3b2344cb7
146450ab2161
1535d3331bc3
hex1e5c955b79

130402311033 has 4 divisors (see below), whose sum is σ = 173869748048. Its totient is φ = 86934874020.

The previous prime is 130402311001. The next prime is 130402311037. The reversal of 130402311033 is 330113204031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 130402311033 - 25 = 130402311001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130402311037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21733718503 + ... + 21733718508.

It is an arithmetic number, because the mean of its divisors is an integer number (43467437012).

Almost surely, 2130402311033 is an apocalyptic number.

It is an amenable number.

130402311033 is a deficient number, since it is larger than the sum of its proper divisors (43467437015).

130402311033 is an equidigital number, since it uses as much as digits as its factorization.

130402311033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43467437014.

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 130402311033 its reverse (330113204031), we get a palindrome (460515515064).

The spelling of 130402311033 in words is "one hundred thirty billion, four hundred two million, three hundred eleven thousand, thirty-three".

Divisors: 1 3 43467437011 130402311033