13040400451 has 4 divisors (see below), whose sum is σ = 14043508192. Its totient is φ = 12037292712.

The previous prime is 13040400437. The next prime is 13040400521. The reversal of 13040400451 is 15400404031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15400404031 = 7247 ⋅2125073.

It is a cyclic number.

It is not a de Polignac number, because 13040400451 - 2⁵ = 13040400419 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13040400251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 501553851 + ... + 501553876.

It is an arithmetic number, because the mean of its divisors is an integer number (3510877048).

Almost surely, 2^13040400451 is an apocalyptic number.

13040400451 is a deficient number, since it is larger than the sum of its proper divisors (1003107741).

13040400451 is a wasteful number, since it uses less digits than its factorization.

13040400451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1003107740.

The product of its (nonzero) digits is 960, while the sum is 22.

Adding to 13040400451 its reverse (15400404031), we get a palindrome (28440804482).

The spelling of 13040400451 in words is "thirteen billion, forty million, four hundred thousand, four hundred fifty-one".