130404035 has 4 divisors (see below), whose sum is σ = 156484848. Its totient is φ = 104323224.

The previous prime is 130404023. The next prime is 130404037. The reversal of 130404035 is 530404031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 530404031 = 5653 ⋅93827.

It is a cyclic number.

It is not a de Polignac number, because 130404035 - 2⁴ = 130404019 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130403998 and 130404016.

It is not an unprimeable number, because it can be changed into a prime (130404037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13040399 + ... + 13040408.

It is an arithmetic number, because the mean of its divisors is an integer number (39121212).

Almost surely, 2^130404035 is an apocalyptic number.

130404035 is a deficient number, since it is larger than the sum of its proper divisors (26080813).

130404035 is an equidigital number, since it uses as much as digits as its factorization.

130404035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26080812.

The product of its (nonzero) digits is 720, while the sum is 20.

The square root of 130404035 is about 11419.4586123861. The cubic root of 130404035 is about 507.1039692270.

Adding to 130404035 its reverse (530404031), we get a palindrome (660808066).

The spelling of 130404035 in words is "one hundred thirty million, four hundred four thousand, thirty-five".