13040431113 has 8 divisors (see below), whose sum is σ = 17389468800. Its totient is φ = 8692507088.

The previous prime is 13040431069. The next prime is 13040431123. The reversal of 13040431113 is 31113404031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13040431113 - 2⁸ = 13040430857 is a prime.

It is a super-2 number, since 2×13040431113² (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13040431113.

It is not an unprimeable number, because it can be changed into a prime (13040431123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 250698 + ... + 298211.

It is an arithmetic number, because the mean of its divisors is an integer number (2173683600).

Almost surely, 2^13040431113 is an apocalyptic number.

It is an amenable number.

13040431113 is a deficient number, since it is larger than the sum of its proper divisors (4349037687).

13040431113 is an equidigital number, since it uses as much as digits as its factorization.

13040431113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 556831.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 13040431113 its reverse (31113404031), we get a palindrome (44153835144).

It can be divided in two parts, 13040 and 431113, that added together give a triangular number (444153 = T₉₄₂).

The spelling of 13040431113 in words is "thirteen billion, forty million, four hundred thirty-one thousand, one hundred thirteen".