13040440202033 has 4 divisors (see below), whose sum is σ = 13044692060400. Its totient is φ = 13036188343668.

The previous prime is 13040440201973. The next prime is 13040440202071. The reversal of 13040440202033 is 33020204404031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13040440202033 - 2²⁰ = 13040439153457 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13040440201993 and 13040440202011.

It is not an unprimeable number, because it can be changed into a prime (13040440252033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2125924583 + ... + 2125930716.

It is an arithmetic number, because the mean of its divisors is an integer number (3261173015100).

Almost surely, 2^{13040440202033} is an apocalyptic number.

It is an amenable number.

13040440202033 is a deficient number, since it is larger than the sum of its proper divisors (4251858367).

13040440202033 is an equidigital number, since it uses as much as digits as its factorization.

13040440202033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4251858366.

The product of its (nonzero) digits is 6912, while the sum is 26.

Adding to 13040440202033 its reverse (33020204404031), we get a palindrome (46060644606064).

The spelling of 13040440202033 in words is "thirteen trillion, forty billion, four hundred forty million, two hundred two thousand, thirty-three".