Search a number
-
+
13041010441 = 13993820219
BaseRepresentation
bin11000010010100111…
…00000011100001001
31020122211221222012201
430021103200130021
5203201444313231
65554014040201
7641111521414
oct141123403411
936584858181
1013041010441
115592346188
12263b4a9061
1312caa30434
148b9da2b7b
15514d53161
hex3094e0709

13041010441 has 4 divisors (see below), whose sum is σ = 13134830800. Its totient is φ = 12947190084.

The previous prime is 13041010397. The next prime is 13041010457. The reversal of 13041010441 is 14401014031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13041010441 - 27 = 13041010313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13041011441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46909971 + ... + 46910248.

It is an arithmetic number, because the mean of its divisors is an integer number (3283707700).

Almost surely, 213041010441 is an apocalyptic number.

It is an amenable number.

13041010441 is a deficient number, since it is larger than the sum of its proper divisors (93820359).

13041010441 is an equidigital number, since it uses as much as digits as its factorization.

13041010441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 93820358.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 13041010441 its reverse (14401014031), we get a palindrome (27442024472).

The spelling of 13041010441 in words is "thirteen billion, forty-one million, ten thousand, four hundred forty-one".

Divisors: 1 139 93820219 13041010441