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130410435403 = 6718311063039
BaseRepresentation
bin111100101110100010…
…0010101001101001011
3110110121112020112011001
41321131010111031023
54114040032413103
6135524300115431
712264456261013
oct1713504251513
9413545215131
10130410435403
1150341322346
1221336235b77
13c3b3c2ac11
146451bc8c43
1535d3dd901d
hex1e5d11534b

130410435403 has 8 divisors (see below), whose sum is σ = 132429271040. Its totient is φ = 128393729640.

The previous prime is 130410435401. The next prime is 130410435427. The reversal of 130410435403 is 304534014031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130410435403 - 21 = 130410435401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130410435401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 408843 + ... + 654196.

It is an arithmetic number, because the mean of its divisors is an integer number (16553658880).

Almost surely, 2130410435403 is an apocalyptic number.

130410435403 is a deficient number, since it is larger than the sum of its proper divisors (2018835637).

130410435403 is a wasteful number, since it uses less digits than its factorization.

130410435403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1064937.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 130410435403 its reverse (304534014031), we get a palindrome (434944449434).

The spelling of 130410435403 in words is "one hundred thirty billion, four hundred ten million, four hundred thirty-five thousand, four hundred three".

Divisors: 1 67 1831 122677 1063039 71223613 1946424409 130410435403