Search a number
-
+
130410435435 = 3571242004147
BaseRepresentation
bin111100101110100010…
…0010101001101101011
3110110121112020112012020
41321131010111031223
54114040032413220
6135524300115523
712264456261060
oct1713504251553
9413545215166
10130410435435
1150341322375
1221336235ba3
13c3b3c2ac37
146451bc8c67
1535d3dd9040
hex1e5d11536b

130410435435 has 16 divisors (see below), whose sum is σ = 238464796416. Its totient is φ = 59616199008.

The previous prime is 130410435427. The next prime is 130410435473. The reversal of 130410435435 is 534534014031.

It is not a de Polignac number, because 130410435435 - 23 = 130410435427 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130410435396 and 130410435405.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 621001969 + ... + 621002178.

It is an arithmetic number, because the mean of its divisors is an integer number (14904049776).

Almost surely, 2130410435435 is an apocalyptic number.

130410435435 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

130410435435 is a deficient number, since it is larger than the sum of its proper divisors (108054360981).

130410435435 is a wasteful number, since it uses less digits than its factorization.

130410435435 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1242004162.

The product of its (nonzero) digits is 43200, while the sum is 33.

Adding to 130410435435 its reverse (534534014031), we get a palindrome (664944449466).

The spelling of 130410435435 in words is "one hundred thirty billion, four hundred ten million, four hundred thirty-five thousand, four hundred thirty-five".

Divisors: 1 3 5 7 15 21 35 105 1242004147 3726012441 6210020735 8694029029 18630062205 26082087087 43470145145 130410435435