13041047657353 has 4 divisors (see below), whose sum is σ = 13041055076868. Its totient is φ = 13041040237840.

The previous prime is 13041047657321. The next prime is 13041047657377. The reversal of 13041047657353 is 35375674014031.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 3791225669449 + 9249821987904 = 1947107^2 + 3041352^2 .

It is a cyclic number.

It is not a de Polignac number, because 13041047657353 - 2⁵ = 13041047657321 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13041047657297 and 13041047657306.

It is not an unprimeable number, because it can be changed into a prime (13041047657303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 580983 + ... + 5140003.

It is an arithmetic number, because the mean of its divisors is an integer number (3260263769217).

Almost surely, 2^{13041047657353} is an apocalyptic number.

It is an amenable number.

13041047657353 is a deficient number, since it is larger than the sum of its proper divisors (7419515).

13041047657353 is an equidigital number, since it uses as much as digits as its factorization.

13041047657353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7419514.

The product of its (nonzero) digits is 3175200, while the sum is 49.

The spelling of 13041047657353 in words is "thirteen trillion, forty-one billion, forty-seven million, six hundred fifty-seven thousand, three hundred fifty-three".