1304112141121 has 4 divisors (see below), whose sum is σ = 1304780575744. Its totient is φ = 1303443706500.

The previous prime is 1304112141119. The next prime is 1304112141131. The reversal of 1304112141121 is 1211412114031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1304112141121 - 2¹ = 1304112141119 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1304112141092 and 1304112141101.

It is not an unprimeable number, because it can be changed into a prime (1304112141131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 334214385 + ... + 334218286.

It is an arithmetic number, because the mean of its divisors is an integer number (326195143936).

Almost surely, 2^{1304112141121} is an apocalyptic number.

It is an amenable number.

1304112141121 is a deficient number, since it is larger than the sum of its proper divisors (668434623).

1304112141121 is an equidigital number, since it uses as much as digits as its factorization.

1304112141121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 668434622.

The product of its (nonzero) digits is 192, while the sum is 22.

Adding to 1304112141121 its reverse (1211412114031), we get a palindrome (2515524255152).

The spelling of 1304112141121 in words is "one trillion, three hundred four billion, one hundred twelve million, one hundred forty-one thousand, one hundred twenty-one".