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130412113 = 1323714231
BaseRepresentation
bin1111100010111…
…10111001010001
3100002101121210021
413301132321101
5231341141423
620535103441
73142325146
oct761367121
9302347707
10130412113
1167683607
1237811b81
1321031240
141346a3cd
15b6b095d
hex7c5ee51

130412113 has 8 divisors (see below), whose sum is σ = 140536256. Its totient is φ = 120301200.

The previous prime is 130412099. The next prime is 130412119. The reversal of 130412113 is 311214031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130412113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130412119) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28708 + ... + 32938.

It is an arithmetic number, because the mean of its divisors is an integer number (17567032).

Almost surely, 2130412113 is an apocalyptic number.

130412113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

130412113 is a deficient number, since it is larger than the sum of its proper divisors (10124143).

130412113 is a wasteful number, since it uses less digits than its factorization.

130412113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6615.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 130412113 is about 11419.8123014347. The cubic root of 130412113 is about 507.1144400208.

Adding to 130412113 its reverse (311214031), we get a palindrome (441626144).

The spelling of 130412113 in words is "one hundred thirty million, four hundred twelve thousand, one hundred thirteen".

Divisors: 1 13 2371 4231 30823 55003 10031701 130412113