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1304210100241 = 2356704786967
BaseRepresentation
bin10010111110101000111…
…110101101000000010001
311121200101122101201000201
4102332220332231000101
5132332010241201431
62435051300415201
7163140353640166
oct22765076550021
94550348351021
101304210100241
11463126667884
121909213a7501
1395ca93cb509
14471a479006d
1523dd384c461
hex12fa8fad011

1304210100241 has 4 divisors (see below), whose sum is σ = 1360914887232. Its totient is φ = 1247505313252.

The previous prime is 1304210100203. The next prime is 1304210100251. The reversal of 1304210100241 is 1420010124031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1304210100241 - 217 = 1304209969169 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1304210100251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28352393461 + ... + 28352393506.

It is an arithmetic number, because the mean of its divisors is an integer number (340228721808).

Almost surely, 21304210100241 is an apocalyptic number.

It is an amenable number.

1304210100241 is a deficient number, since it is larger than the sum of its proper divisors (56704786991).

1304210100241 is an equidigital number, since it uses as much as digits as its factorization.

1304210100241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56704786990.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 1304210100241 its reverse (1420010124031), we get a palindrome (2724220224272).

The spelling of 1304210100241 in words is "one trillion, three hundred four billion, two hundred ten million, one hundred thousand, two hundred forty-one".

Divisors: 1 23 56704786967 1304210100241