Base | Representation |
---|---|
bin | 11000010010101111… |
… | …01010101110000001 |
3 | 1020122221000101100021 |
4 | 30021113222232001 |
5 | 203202234213441 |
6 | 5554053253441 |
7 | 641124013300 |
oct | 141127525601 |
9 | 36587011307 |
10 | 13042101121 |
11 | 5592a20675 |
12 | 263b934281 |
13 | 12cb0229ca |
14 | 8ba1a8437 |
15 | 514ebb3d1 |
hex | 3095eab81 |
13042101121 has 6 divisors (see below), whose sum is σ = 15171423810. Its totient is φ = 11178943776.
The previous prime is 13042101119. The next prime is 13042101151. The reversal of 13042101121 is 12110124031.
It can be written as a sum of positive squares in only one way, i.e., 11172490000 + 1869611121 = 105700^2 + 43239^2 .
It is not a de Polignac number, because 13042101121 - 21 = 13042101119 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13042101095 and 13042101104.
It is not an unprimeable number, because it can be changed into a prime (13042101101) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 133082616 + ... + 133082713.
It is an arithmetic number, because the mean of its divisors is an integer number (2528570635).
Almost surely, 213042101121 is an apocalyptic number.
It is an amenable number.
13042101121 is a deficient number, since it is larger than the sum of its proper divisors (2129322689).
13042101121 is an equidigital number, since it uses as much as digits as its factorization.
13042101121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 266165343 (or 266165336 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 13042101121 its reverse (12110124031), we get a palindrome (25152225152).
The spelling of 13042101121 in words is "thirteen billion, forty-two million, one hundred one thousand, one hundred twenty-one".
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