13042326541345 has 4 divisors (see below), whose sum is σ = 15650791849620. Its totient is φ = 10433861233072.

The previous prime is 13042326541319. The next prime is 13042326541369. The reversal of 13042326541345 is 54314562324031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10117227816081 + 2925098725264 = 3180759^2 + 1710292^2 .

It is a cyclic number.

It is not a de Polignac number, because 13042326541345 - 2²⁵ = 13042292986913 is a prime.

It is a super-2 number, since 2×13042326541345² (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1304232654130 + ... + 1304232654139.

It is an arithmetic number, because the mean of its divisors is an integer number (3912697962405).

Almost surely, 2^{13042326541345} is an apocalyptic number.

It is an amenable number.

13042326541345 is a deficient number, since it is larger than the sum of its proper divisors (2608465308275).

13042326541345 is an equidigital number, since it uses as much as digits as its factorization.

13042326541345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2608465308274.

The product of its (nonzero) digits is 1036800, while the sum is 43.

Adding to 13042326541345 its reverse (54314562324031), we get a palindrome (67356888865376).

The spelling of 13042326541345 in words is "thirteen trillion, forty-two billion, three hundred twenty-six million, five hundred forty-one thousand, three hundred forty-five".