1304251413331 has 4 divisors (see below), whose sum is σ = 1334582841592. Its totient is φ = 1273919985072.

The previous prime is 1304251413317. The next prime is 1304251413379. The reversal of 1304251413331 is 1333141524031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1304251413331 - 2⁷ = 1304251413203 is a prime.

It is a super-2 number, since 2×1304251413331² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1304251413293 and 1304251413302.

It is not an unprimeable number, because it can be changed into a prime (1304251413631) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15165714066 + ... + 15165714151.

It is an arithmetic number, because the mean of its divisors is an integer number (333645710398).

Almost surely, 2^{1304251413331} is an apocalyptic number.

1304251413331 is a deficient number, since it is larger than the sum of its proper divisors (30331428261).

1304251413331 is an equidigital number, since it uses as much as digits as its factorization.

1304251413331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30331428260.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 1304251413331 its reverse (1333141524031), we get a palindrome (2637392937362).

The spelling of 1304251413331 in words is "one trillion, three hundred four billion, two hundred fifty-one million, four hundred thirteen thousand, three hundred thirty-one".