Base | Representation |
---|---|
bin | 11000010010110101… |
… | …01000000111010001 |
3 | 1020122222110210111010 |
4 | 30021122220013101 |
5 | 203202434030011 |
6 | 5554122041133 |
7 | 641133424056 |
oct | 141132500721 |
9 | 36588423433 |
10 | 13042876881 |
11 | 55934004a1 |
12 | 26400491a9 |
13 | 12cb234b38 |
14 | 8ba32b02d |
15 | 5150c11a6 |
hex | 3096a81d1 |
13042876881 has 4 divisors (see below), whose sum is σ = 17390502512. Its totient is φ = 8695251252.
The previous prime is 13042876877. The next prime is 13042876883. The reversal of 13042876881 is 18867824031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 13042876881 - 22 = 13042876877 is a prime.
It is a super-2 number, since 2×130428768812 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 13042876881.
It is not an unprimeable number, because it can be changed into a prime (13042876883) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2173812811 + ... + 2173812816.
It is an arithmetic number, because the mean of its divisors is an integer number (4347625628).
Almost surely, 213042876881 is an apocalyptic number.
It is an amenable number.
13042876881 is a deficient number, since it is larger than the sum of its proper divisors (4347625631).
13042876881 is an equidigital number, since it uses as much as digits as its factorization.
13042876881 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4347625630.
The product of its (nonzero) digits is 516096, while the sum is 48.
The spelling of 13042876881 in words is "thirteen billion, forty-two million, eight hundred seventy-six thousand, eight hundred eighty-one".
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