Base | Representation |
---|---|
bin | 11000010010110111… |
… | …01011000100001001 |
3 | 1020122222222201122212 |
4 | 30021123223010021 |
5 | 203203021313423 |
6 | 5554131554505 |
7 | 641135645426 |
oct | 141133530411 |
9 | 36588881585 |
10 | 13043151113 |
11 | 5593578533 |
12 | 264015ba35 |
13 | 12cb2cc8c5 |
14 | 8ba39cd4d |
15 | 515127578 |
hex | 3096eb109 |
13043151113 has 4 divisors (see below), whose sum is σ = 13044070608. Its totient is φ = 13042231620.
The previous prime is 13043151083. The next prime is 13043151131. The reversal of 13043151113 is 31115134031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13043151113 - 26 = 13043151049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13043151193) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 438131 + ... + 466952.
It is an arithmetic number, because the mean of its divisors is an integer number (3261017652).
Almost surely, 213043151113 is an apocalyptic number.
It is an amenable number.
13043151113 is a deficient number, since it is larger than the sum of its proper divisors (919495).
13043151113 is an equidigital number, since it uses as much as digits as its factorization.
13043151113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 919494.
The product of its (nonzero) digits is 540, while the sum is 23.
Adding to 13043151113 its reverse (31115134031), we get a palindrome (44158285144).
The spelling of 13043151113 in words is "thirteen billion, forty-three million, one hundred fifty-one thousand, one hundred thirteen".
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