Base | Representation |
---|---|
bin | 11101101010000011100110… |
… | …111110100101010100101011 |
3 | 122002211022111211121210202211 |
4 | 131222003212332211110223 |
5 | 114044010142123313121 |
6 | 1141224143540305551 |
7 | 36321335200046221 |
oct | 3552034676452453 |
9 | 562738454553684 |
10 | 130433442010411 |
11 | 3861856a692a61 |
12 | 12766a5b9a22b7 |
13 | 57a1a89400067 |
14 | 242d025990b11 |
15 | 1012d16d70ce1 |
hex | 76a0e6fa552b |
130433442010411 has 4 divisors (see below), whose sum is σ = 132270532743024. Its totient is φ = 128596351277800.
The previous prime is 130433442010379. The next prime is 130433442010427. The reversal of 130433442010411 is 114010244334031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130433442010411 - 25 = 130433442010379 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130433442010451) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 918545366200 + ... + 918545366341.
It is an arithmetic number, because the mean of its divisors is an integer number (33067633185756).
Almost surely, 2130433442010411 is an apocalyptic number.
130433442010411 is a deficient number, since it is larger than the sum of its proper divisors (1837090732613).
130433442010411 is an equidigital number, since it uses as much as digits as its factorization.
130433442010411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1837090732612.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 130433442010411 its reverse (114010244334031), we get a palindrome (244443686344442).
The spelling of 130433442010411 in words is "one hundred thirty trillion, four hundred thirty-three billion, four hundred forty-two million, ten thousand, four hundred eleven".
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