Base | Representation |
---|---|
bin | 11000010010111001… |
… | …01001000011001001 |
3 | 1020200000110121221010 |
4 | 30021130221003021 |
5 | 203203102430001 |
6 | 5554141234133 |
7 | 641141053554 |
oct | 141134510311 |
9 | 36600417833 |
10 | 13043405001 |
11 | 5593731260 |
12 | 2640262949 |
13 | 12cb38b333 |
14 | 8ba42769b |
15 | 5151778d6 |
hex | 3097290c9 |
13043405001 has 16 divisors (see below), whose sum is σ = 18974340288. Its totient is φ = 7904212800.
The previous prime is 13043404973. The next prime is 13043405009. The reversal of 13043405001 is 10050434031.
It is not a de Polignac number, because 13043405001 - 27 = 13043404873 is a prime.
It is a super-2 number, since 2×130434050012 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13043405009) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 398095 + ... + 429611.
It is an arithmetic number, because the mean of its divisors is an integer number (1185896268).
Almost surely, 213043405001 is an apocalyptic number.
13043405001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
13043405001 is a deficient number, since it is larger than the sum of its proper divisors (5930935287).
13043405001 is a wasteful number, since it uses less digits than its factorization.
13043405001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44072.
The product of its (nonzero) digits is 720, while the sum is 21.
Adding to 13043405001 its reverse (10050434031), we get a palindrome (23093839032).
The spelling of 13043405001 in words is "thirteen billion, forty-three million, four hundred five thousand, one".
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