Base | Representation |
---|---|
bin | 11101101010000100100010… |
… | …101110011001100101101011 |
3 | 122002211102002200210112011022 |
4 | 131222010202232121211223 |
5 | 114044014220231313003 |
6 | 1141224431225123055 |
7 | 36321402061164611 |
oct | 3552044256314553 |
9 | 562742080715138 |
10 | 130434444401003 |
11 | 38618a34499936 |
12 | 1276709b62948b |
13 | 57a1bb8c963a2 |
14 | 242d0bcb616b1 |
15 | 1012d74d75738 |
hex | 76a122b9996b |
130434444401003 has 4 divisors (see below), whose sum is σ = 134642007123648. Its totient is φ = 126226881678360.
The previous prime is 130434444400991. The next prime is 130434444401059. The reversal of 130434444401003 is 300104444434031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130434444401003 - 222 = 130434440206699 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130434447401003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2103781361276 + ... + 2103781361337.
It is an arithmetic number, because the mean of its divisors is an integer number (33660501780912).
Almost surely, 2130434444401003 is an apocalyptic number.
130434444401003 is a deficient number, since it is larger than the sum of its proper divisors (4207562722645).
130434444401003 is an equidigital number, since it uses as much as digits as its factorization.
130434444401003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4207562722644.
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 130434444401003 its reverse (300104444434031), we get a palindrome (430538888835034).
The spelling of 130434444401003 in words is "one hundred thirty trillion, four hundred thirty-four billion, four hundred forty-four million, four hundred one thousand, three".
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