13044000003 has 4 divisors (see below), whose sum is σ = 17392000008. Its totient is φ = 8696000000.

The previous prime is 13044000001. The next prime is 13044000037. The reversal of 13044000003 is 30000044031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13044000003 - 2¹ = 13044000001 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13044000001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2173999998 + ... + 2174000003.

It is an arithmetic number, because the mean of its divisors is an integer number (4348000002).

Almost surely, 2^13044000003 is an apocalyptic number.

13044000003 is a deficient number, since it is larger than the sum of its proper divisors (4348000005).

13044000003 is an equidigital number, since it uses as much as digits as its factorization.

13044000003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4348000004.

The product of its (nonzero) digits is 144, while the sum is 15.

Adding to 13044000003 its reverse (30000044031), we get a palindrome (43044044034).

The spelling of 13044000003 in words is "thirteen billion, forty-four million, three", and thus it is an aban number.