Base | Representation |
---|---|
bin | 11101101010001001101101… |
… | …111000100001001110001011 |
3 | 122002211221102220020001112012 |
4 | 131222021231320201032023 |
5 | 114044112110034442303 |
6 | 1141231150415410135 |
7 | 36321656543513501 |
oct | 3552115570411613 |
9 | 562757386201465 |
10 | 130440000312203 |
11 | 3862032568118a |
12 | 1276819022394b |
13 | 57a2593054bca |
14 | 242d4889b0671 |
15 | 101309c9db5d8 |
hex | 76a26de2138b |
130440000312203 has 4 divisors (see below), whose sum is σ = 131193988753488. Its totient is φ = 129686011870920.
The previous prime is 130440000312169. The next prime is 130440000312241. The reversal of 130440000312203 is 302213000044031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130440000312203 - 216 = 130440000246667 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130440000315203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 376994220383 + ... + 376994220728.
It is an arithmetic number, because the mean of its divisors is an integer number (32798497188372).
Almost surely, 2130440000312203 is an apocalyptic number.
130440000312203 is a deficient number, since it is larger than the sum of its proper divisors (753988441285).
130440000312203 is an equidigital number, since it uses as much as digits as its factorization.
130440000312203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 753988441284.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 130440000312203 its reverse (302213000044031), we get a palindrome (432653000356234).
The spelling of 130440000312203 in words is "one hundred thirty trillion, four hundred forty billion, three hundred twelve thousand, two hundred three".
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