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130440000312203 = 173753988441111
BaseRepresentation
bin11101101010001001101101…
…111000100001001110001011
3122002211221102220020001112012
4131222021231320201032023
5114044112110034442303
61141231150415410135
736321656543513501
oct3552115570411613
9562757386201465
10130440000312203
113862032568118a
121276819022394b
1357a2593054bca
14242d4889b0671
15101309c9db5d8
hex76a26de2138b

130440000312203 has 4 divisors (see below), whose sum is σ = 131193988753488. Its totient is φ = 129686011870920.

The previous prime is 130440000312169. The next prime is 130440000312241. The reversal of 130440000312203 is 302213000044031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130440000312203 - 216 = 130440000246667 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130440000315203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 376994220383 + ... + 376994220728.

It is an arithmetic number, because the mean of its divisors is an integer number (32798497188372).

Almost surely, 2130440000312203 is an apocalyptic number.

130440000312203 is a deficient number, since it is larger than the sum of its proper divisors (753988441285).

130440000312203 is an equidigital number, since it uses as much as digits as its factorization.

130440000312203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 753988441284.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 130440000312203 its reverse (302213000044031), we get a palindrome (432653000356234).

The spelling of 130440000312203 in words is "one hundred thirty trillion, four hundred forty billion, three hundred twelve thousand, two hundred three".

Divisors: 1 173 753988441111 130440000312203