130440001133233 has 4 divisors (see below), whose sum is σ = 142298183054448. Its totient is φ = 118581819212020.

The previous prime is 130440001133213. The next prime is 130440001133297. The reversal of 130440001133233 is 332331100044031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130440001133233 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130440001133213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5929090960591 + ... + 5929090960612.

It is an arithmetic number, because the mean of its divisors is an integer number (35574545763612).

Almost surely, 2^{130440001133233} is an apocalyptic number.

It is an amenable number.

130440001133233 is a deficient number, since it is larger than the sum of its proper divisors (11858181921215).

130440001133233 is a wasteful number, since it uses less digits than its factorization.

130440001133233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11858181921214.

The product of its (nonzero) digits is 7776, while the sum is 28.

Adding to 130440001133233 its reverse (332331100044031), we get a palindrome (462771101177264).

The spelling of 130440001133233 in words is "one hundred thirty trillion, four hundred forty billion, one million, one hundred thirty-three thousand, two hundred thirty-three".