1304400120521 has 4 divisors (see below), whose sum is σ = 1326508597200. Its totient is φ = 1282291643844.

The previous prime is 1304400120509. The next prime is 1304400120523. The reversal of 1304400120521 is 1250210044031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1304400120521 - 2¹⁰ = 1304400119497 is a prime.

It is a super-2 number, since 2×1304400120521² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1304400120523) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11054238251 + ... + 11054238368.

It is an arithmetic number, because the mean of its divisors is an integer number (331627149300).

Almost surely, 2^{1304400120521} is an apocalyptic number.

It is an amenable number.

1304400120521 is a deficient number, since it is larger than the sum of its proper divisors (22108476679).

1304400120521 is an equidigital number, since it uses as much as digits as its factorization.

1304400120521 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22108476678.

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 1304400120521 its reverse (1250210044031), we get a palindrome (2554610164552).

The spelling of 1304400120521 in words is "one trillion, three hundred four billion, four hundred million, one hundred twenty thousand, five hundred twenty-one".