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1304400420201 = 33141591384013
BaseRepresentation
bin10010111110110100010…
…100101101110101101001
311121200212220111221221010
4102332310110231311221
5132332403001421301
62435122215534133
7163145154426654
oct22766424556551
94550786457833
101304400420201
11463214038aaa
1219097508a349
1396009976788
14471c1b7289b
1523de53e35d6
hex12fb452dd69

1304400420201 has 8 divisors (see below), whose sum is σ = 1739207352960. Its totient is φ = 869596883792.

The previous prime is 1304400420187. The next prime is 1304400420203. The reversal of 1304400420201 is 1020240044031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1304400420201 - 26 = 1304400420137 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1304400420203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 250471 + ... + 1634483.

It is an arithmetic number, because the mean of its divisors is an integer number (217400919120).

Almost surely, 21304400420201 is an apocalyptic number.

It is an amenable number.

1304400420201 is a deficient number, since it is larger than the sum of its proper divisors (434806932759).

1304400420201 is a wasteful number, since it uses less digits than its factorization.

1304400420201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1698175.

The product of its (nonzero) digits is 768, while the sum is 21.

Adding to 1304400420201 its reverse (1020240044031), we get a palindrome (2324640464232).

The spelling of 1304400420201 in words is "one trillion, three hundred four billion, four hundred million, four hundred twenty thousand, two hundred one".

Divisors: 1 3 314159 942477 1384013 4152039 434800140067 1304400420201