130440102113 has 4 divisors (see below), whose sum is σ = 130449601728. Its totient is φ = 130430602500.

The previous prime is 130440102083. The next prime is 130440102209. The reversal of 130440102113 is 311201044031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311201044031 = 397 ⋅783881723.

It is a cyclic number.

It is not a de Polignac number, because 130440102113 - 2¹⁸ = 130439839969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130440102413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4729181 + ... + 4756682.

It is an arithmetic number, because the mean of its divisors is an integer number (32612400432).

Almost surely, 2^130440102113 is an apocalyptic number.

It is an amenable number.

130440102113 is a deficient number, since it is larger than the sum of its proper divisors (9499615).

130440102113 is an equidigital number, since it uses as much as digits as its factorization.

130440102113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9499614.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 130440102113 its reverse (311201044031), we get a palindrome (441641146144).

The spelling of 130440102113 in words is "one hundred thirty billion, four hundred forty million, one hundred two thousand, one hundred thirteen".