13044012320043 has 16 divisors (see below), whose sum is σ = 19651995964800. Its totient is φ = 8548618242600.

The previous prime is 13044012319999. The next prime is 13044012320077. The reversal of 13044012320043 is 34002321044031.

13044012320043 is a `hidden beast` number, since 1 + 3 + 0 + 440 + 12 + 3 + 200 + 4 + 3 = 666.

It is a de Polignac number, because none of the positive numbers 2^k-13044012320043 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 13044012319989 and 13044012320016.

It is not an unprimeable number, because it can be changed into a prime (13044012320743) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4094164233 + ... + 4094167418.

It is an arithmetic number, because the mean of its divisors is an integer number (1228249747800).

Almost surely, 2^{13044012320043} is an apocalyptic number.

13044012320043 is a deficient number, since it is larger than the sum of its proper divisors (6607983644757).

13044012320043 is an equidigital number, since it uses as much as digits as its factorization.

13044012320043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8188331719 (or 8188331713 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 13044012320043 its reverse (34002321044031), we get a palindrome (47046333364074).

The spelling of 13044012320043 in words is "thirteen trillion, forty-four billion, twelve million, three hundred twenty thousand, forty-three".