Base | Representation |
---|---|
bin | 11101101010001001111100… |
… | …001110110101001110100011 |
3 | 122002211222001200012102012011 |
4 | 131222021330032311032203 |
5 | 114044113103201323324 |
6 | 1141231230335213351 |
7 | 36321665525626564 |
oct | 3552117416651643 |
9 | 562758050172164 |
10 | 130440241042339 |
11 | 38620439553308 |
12 | 12768238977257 |
13 | 57a2600ba0187 |
14 | 242d4ac95616b |
15 | 10130b3bddc94 |
hex | 76a27c3b53a3 |
130440241042339 has 4 divisors (see below), whose sum is σ = 130646960917840. Its totient is φ = 130233521166840.
The previous prime is 130440241042283. The next prime is 130440241042379. The reversal of 130440241042339 is 933240142044031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130440241042339 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130440241042379) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 103359936804 + ... + 103359938065.
It is an arithmetic number, because the mean of its divisors is an integer number (32661740229460).
Almost surely, 2130440241042339 is an apocalyptic number.
130440241042339 is a deficient number, since it is larger than the sum of its proper divisors (206719875501).
130440241042339 is an equidigital number, since it uses as much as digits as its factorization.
130440241042339 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 206719875500.
The product of its (nonzero) digits is 248832, while the sum is 40.
The spelling of 130440241042339 in words is "one hundred thirty trillion, four hundred forty billion, two hundred forty-one million, forty-two thousand, three hundred thirty-nine".
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