130441044030041 has 4 divisors (see below), whose sum is σ = 130441083493284. Its totient is φ = 130441004566800.

The previous prime is 130441044030013. The next prime is 130441044030043. The reversal of 130441044030041 is 140030440144031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 40084536625225 + 90356507404816 = 6331235^2 + 9505604^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130441044030041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130441044029986 and 130441044030013.

It is not an unprimeable number, because it can be changed into a prime (130441044030043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14269550 + ... + 21552311.

It is an arithmetic number, because the mean of its divisors is an integer number (32610270873321).

Almost surely, 2^{130441044030041} is an apocalyptic number.

It is an amenable number.

130441044030041 is a deficient number, since it is larger than the sum of its proper divisors (39463243).

130441044030041 is an equidigital number, since it uses as much as digits as its factorization.

130441044030041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 39463242.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 130441044030041 its reverse (140030440144031), we get a palindrome (270471484174072).

The spelling of 130441044030041 in words is "one hundred thirty trillion, four hundred forty-one billion, forty-four million, thirty thousand, forty-one".