Base | Representation |
---|---|
bin | 11101101010001010101100… |
… | …000101111111001100100011 |
3 | 122002212001010122011102111220 |
4 | 131222022230011333030203 |
5 | 114044121224232431433 |
6 | 1141231442142110123 |
7 | 36322024446126312 |
oct | 3552125405771443 |
9 | 562761118142456 |
10 | 130441044030243 |
11 | 38620810844a81 |
12 | 1276842187b343 |
13 | 57a26cb35b04b |
14 | 242d54745c279 |
15 | 101310e4562b3 |
hex | 76a2ac17f323 |
130441044030243 has 8 divisors (see below), whose sum is σ = 178621970203728. Its totient is φ = 84610406938464.
The previous prime is 130441044030239. The next prime is 130441044030287. The reversal of 130441044030243 is 342030440144031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 130441044030243 - 22 = 130441044030239 is a prime.
It is not an unprimeable number, because it can be changed into a prime (130441044030203) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 587572270296 + ... + 587572270517.
It is an arithmetic number, because the mean of its divisors is an integer number (22327746275466).
Almost surely, 2130441044030243 is an apocalyptic number.
130441044030243 is a deficient number, since it is larger than the sum of its proper divisors (48180926173485).
130441044030243 is a wasteful number, since it uses less digits than its factorization.
130441044030243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1175144540853.
The product of its (nonzero) digits is 55296, while the sum is 33.
Adding to 130441044030243 its reverse (342030440144031), we get a palindrome (472471484174274).
The spelling of 130441044030243 in words is "one hundred thirty trillion, four hundred forty-one billion, forty-four million, thirty thousand, two hundred forty-three".
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