1304413442331 has 4 divisors (see below), whose sum is σ = 1739217923112. Its totient is φ = 869608961552.

The previous prime is 1304413442263. The next prime is 1304413442363. The reversal of 1304413442331 is 1332443144031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1304413442331 - 2²² = 1304409248027 is a prime.

It is a super-2 number, since 2×1304413442331² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1304413442292 and 1304413442301.

It is not an unprimeable number, because it can be changed into a prime (1304413442531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 217402240386 + ... + 217402240391.

It is an arithmetic number, because the mean of its divisors is an integer number (434804480778).

Almost surely, 2^{1304413442331} is an apocalyptic number.

1304413442331 is a deficient number, since it is larger than the sum of its proper divisors (434804480781).

1304413442331 is an equidigital number, since it uses as much as digits as its factorization.

1304413442331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 434804480780.

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 1304413442331 its reverse (1332443144031), we get a palindrome (2636856586362).

The spelling of 1304413442331 in words is "one trillion, three hundred four billion, four hundred thirteen million, four hundred forty-two thousand, three hundred thirty-one".